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                        MR=D3WCZY=D1SKI </TD></TR>
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                      <TD class=3Dtytul vAlign=3Dtop align=3Dleft>TRZY =
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                        LEPTON=D3W</TD></TR>
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                                <TD align=3Dmiddle><IMG height=3D120=20
                                alt=3D"Wiedza i =AFycie nr 3/1996"=20
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                                <TR>
                                <TD class=3Dokladkapodpis =
align=3Dmiddle>Artyku=B3=20
                                pochodzi z "Wiedzy i =AFycia" nr =
3/1996</TD></TR>
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                        <P class=3Dwstep><B>Nagrod=EA Nobla z fizyki w =
roku 1995=20
                        przyznano badaczom cz=B1stek elementarnych, =
kt=F3re nale=BF=B1=20
                        do grupy lepton=F3w. Uhonorowani zostali: =
Frederick Reines=20
                        za obserwacj=EA nieuchwytnego neutrina oraz =
Martin L. Perl=20
                        za odkrycie cz=B1stki tau. </B></P>
                        <P class=3Dtekst><A=20
                        =
href=3D"http://archiwum.wiz.pl/1996/96031800.asp#FRED"=20
                        ?960318001?>Frederick Reines</A><BR><A=20
                        =
href=3D"http://archiwum.wiz.pl/1996/96031800.asp#MARTI"=20
                        ?960318002?>Martin L. Perl</A><BR><BR></P>
                        <P class=3Dtekst>Gdy w kwietniu 1994 roku =
zaobserwowano=20
                        przewidziany niemal 20 lat wcze=B6niej sz=F3sty =
kwark, Model=20
                        Standardowy, wyra=BFaj=B1cy najpe=B3niej nasz=B1 =
wiedz=EA o=20
                        elementarnych sk=B3adnikach materii, znalaz=B3 =
wspania=B3e=20
                        potwierdzenie. Znaleziono ostatni klocek =
skomplikowanej=20
                        uk=B3adanki, kt=F3r=B1 z mozo=B3em budowano =
przez=20
                        dziesi=EAciolecia. Jest ona teraz kompletna - =
wszystkie=20
                        klocki idealnie do siebie pasuj=B1, =BFadnego =
nie mo=BFna=20
                        usun=B1=E6 ani doda=E6. Ubieg=B3oroczni =
nobli=B6ci Frederick=20
                        Reines i Martin L. Perl walnie przyczynili si=EA =
do tego=20
                        sukcesu, dostarczaj=B1c kolejne klocki. Ich =
odkrycia=20
                        sprzed lat - neutrino zaobserwowano w roku 1956, =
a=20
                        cz=B1stk=EA tau w 1974 - ja=B6niej=B1 teraz =
pe=B3nym blaskiem.</P>
                        <P class=3Dtekst>Dzieje i charakter odkry=E6 =
Reinesa i Perla=20
                        s=B1 ca=B3kiem odmienne, cho=E6 dotycz=B1 tej =
samej grupy=20
                        cz=B1stek elementarnych zwanych leptonami. =
Rejestracja=20
                        neutrina, kt=F3rego istnienie przewidziano =
teoretycznie=20
                        dwie dekady wcze=B6niej, by=B3a wydarzeniem =
d=B3ugo=20
                        wyczekiwanym. Wierzono, =BFe wcze=B6niej czy =
p=F3=BCniej uda si=EA=20
                        pojma=E6 t=EA cz=B1stk=EA - widmo. Nale=BFa=B3o =
jednak znale=BC=E6=20
                        metod=EA i pokona=E6 ogromne trudno=B6ci =
techniczne. Odkrycie=20
                        leptonu tau by=B3o za=B6 zupe=B3nym =
zaskoczeniem. Nie=20
                        potrzebowano wszak jeszcze jednego okazu do i =
tak ju=BF=20
                        licznej mena=BFerii cz=B1stek elementarnych.</P>
                        <P class=3Dtekst>Zacznijmy od neutrina, gdy=BF =
poznawanie=20
                        jego w=B3asno=B6ci towarzyszy=B3o procesowi =
kszta=B3towania si=EA=20
                        wsp=F3=B3czesnego obrazu struktury materii =
niemal od=20
                        pocz=B1tku, dok=B3adniej od roku 1930. Ju=BF =
wtedy wiedziano,=20
                        =BFe atom tworz=B1 elektrony kr=B1=BF=B1ce =
wok=F3=B3 j=B1dra atomowego,=20
                        a protony, b=EAd=B1ce j=B1drami atomu wodoru, =
s=B1 sk=B3adnikmi=20
                        ci=EA=BFszych j=B1der. Obserwowano zjawisko=20
                        promieniotw=F3rczo=B6ci naturalnej, w kt=F3rym =
spontanicznie=20
                        nast=EApowa=B3a transmutacja pierwiastk=F3w, =
dzi=EAki przemianie=20
                        jednego j=B1dra w drugie.</P>
                        <P class=3Dsrodtytul>NIEWIDZIALNA CZ=A1STKA </P>
                        <P class=3Dtekst>Szczeg=F3lnie wiele uwagi =
po=B6wi=EAcono=20
                        badaniu tzw. rozpadu beta (Patrz: Zdumiewaj=B1cy =
rozpad=20
                        beta, "Wi=AF", nr 6/1995), w kt=F3rym j=B1dro o =
=B3adunku Ze,=20
                        gdzie e jest =B3adunkiem elementarnym, emituje =
elektron i=20
                        zamienia si=EA w j=B1dro nios=B1ce =B3adunek =
(Z+1)e. Wieloletnie=20
                        badania tego procesu, zdawa=B3y si=EA =
wskazywa=E6, =BFe =B3=B1czna=20
                        energia produkt=F3w rozpadu jest mniejsza ni=BF =
energia=20
                        pocz=B1tkowa. Znaczy=B3oby to, =BFe jedno z =
najbardziej=20
                        fundamentalnych praw fizyki - zasada zachowania =
energii=20
                        - jest gwa=B3cone w reakcjach j=B1drowych. =
Energia wszak=20
                        mo=BFe zmienia=E6 swoj=B1 form=EA, =
przekszta=B3ca=E6 si=EA np. z=20
                        kinetycznej w potencjaln=B1 lub z cieplnej w =
elektryczn=B1,=20
                        nie mo=BFe jednak ani zanika=E6, ani rodzi=E6 =
si=EA z=20
                        niczego.</P>
                        <P class=3Dtekst>Gdy dopuszczano ju=BF my=B6l, =
=BFe zasada ta=20
                        rzeczywi=B6cie nie stosuje si=EA do proces=F3w =
j=B1drowych,=20
                        Wolfgang Pauli znalaz=B3 cudownie proste=20
                        rozwi=B1zanie"energetycznego kryzysu". Doszed=B3 =
mianowicie=20
                        do wniosku, =BFe brakuj=B1c=B1 energi=EA unosi =
nieobserwowana=20
                        cz=B1stka. Nazwa=B3 j=B1 neutronem. Sw=F3j =
pomys=B3 sformu=B3owa=B3 w=20
                        grudniu 1930 roku w li=B6cie do zebranych w =
Tybindze=20
                        fizyk=F3w; Pauli zacz=B1=B3 =F3w list s=B3owami: =
Drodzy=20
                        Radioaktywni Panie i Panowie, a zako=F1czy=B3 =
wyja=B6nieniem,=20
                        =BFe do Tybingi przyjecha=E6 nie mo=BFe, ze =
wzgl=EAdu na ta=F1ce,=20
                        odbywaj=B1ce si=EA w Zurichu.</P>
                        <P class=3Dtekst>Nazw=EA neutron nadano =
ostatecznie=20
                        odkrytemu w 1932 roku drugiemu, obok protonu,=20
                        sk=B3adnikowi j=B1dra atomowego. Cz=B1stk=EA, o =
kt=F3rej my=B6la=B3=20
                        Pauli, ochrzczono jako neutrino, co jest =
w=B3oskim=20
                        zdrobnieniem neutronu. Ojcem chrzestnym by=B3 =
wielki W=B3och=20
                        Enerico Fermi, kt=F3ry ju=BF 1934 roku =
zaproponowa=B3 teori=EA=20
                        oddzia=B3ywa=F1 neutrin. Ciekawe, =BFe redakcja =
presti=BFowego=20
                        czasopisma "Nature"odrzuci=B3a pierwsz=B1 =
prac=EA po=B6wi=EAcon=B1=20
                        tej, poprawnej jak dzisiaj wiemy, teorii jako=20
                        zawieraj=B1c=B1 "spekulacje zbyt dalekie od=20
                        rzeczywisto=B6ci".</P>
                        <P class=3Dsrodtytul>ODDZIA=A3YWANIA S=A3ABE =
</P>
                        <P class=3Dtekst>W =B6wiecie nas otaczaj=B1cym =
ujawniaj=B1 si=EA=20
                        tylko si=B3y grawitacyjne i elektromagnetyczne. =
Obiektami=20
                        najmniejszymi we Wszech=B6wiecie rz=B1dz=B1 =
za=B6 jeszcze dwa=20
                        inne oddzia=B3ywania, tzw. silne, kt=F3re, w =
szczeg=F3lno=B6ci,=20
                        wi=B1=BF=B1 neutrony i protony w j=B1dra atomowe =
oraz, tzw.=20
                        s=B3abe, odpowiedzialne mi=EAdzy innymi za =
rozpad beta.=20
                        Fermi sformu=B3owa=B3 teori=EA w=B3a=B6nie si=B3 =
s=B3abych, kt=F3re w=20
                        przeciwie=F1stwie do silnych s=B1, istotnie, =
bardzo ma=B3o=20
                        intensywne. W teorii Fermiego neutrino - dzisiaj =

                        powiedzieliby=B6my neutrino elektronowe - =
wyst=EApuje jako=20
                        partner elektronu. Rzeczywi=B6cie, cz=B1stki te =
maj=B1 pewne=20
                        cechy wsp=F3lne. Neutrino, podobnie jak =
elektron,=20
                        zachowuje si=EA niby wiruj=B1cy b=B1k, tzn. =
obdarzone jest=20
                        spinem. Okazuje si=EA r=F3wnie=BF, =BFe =
zar=F3wno elektrycznie=20
                        na=B3adowany elektron, jak i elektrycznie =
neutralne=20
                        neutrino nios=B1 specyficzny =B3adunek - zwany =
wsp=F3=B3cze=B6nie=20
                        leptonowym, kt=F3ry podobnie jak =B3adunek =
elektryczny jest=20
                        zachowywany. Pozyton, czyli antycz=B1stka =
elektronu, oraz=20
                        antyneutrino, b=EAd=B1ce antycz=B1stk=B1 =
neutrina, nios=B1 =B3adunki=20
                        leptonowe przeciwne ni=BF, odpowiednio, elektron =
i=20
                        neutrino.</P>
                        <P class=3Dtekst>W <A=20
                        =
href=3D"http://archiwum.wiz.pl/1996/96031803.avi"=20
                        ?960318003?>rozpadzie beta</A> neutron n =
zamienia si=EA na=20
                        proton p, elektron e<SUP>-</SUP>oraz =
antyneutrino=20
                        elektronowe, co zapisujemy jako<BR>n --&gt; p +=20
                        e<SUP>-</SUP> + <I>v</I><SUP>-</SUP><SUB>e</SUB> =

                        <BR>=A3adunek elektryczny jest oczywi=B6cie =
zachowany w tym=20
                        procesie, gdy=BF neutron jest elektrycznie =
oboj=EAtny, a=20
                        =B3adunki dodatnio na=B3adowanego protonu i =
nios=B1cego ujemny=20
                        =B3adunek elektronu znosz=B1 si=EA. =A3adunek =
leptonowy jest=20
                        r=F3wnie=BF zachowany, gdy=BF neutron i proton =
maj=B1 zerowe=20
                        =B3adunki leptonowe za=B6 elektron i =
antyneutrino=20
                        elektronowe =B3adunki sobie przeciwne.</P>
                        <P class=3Dtekst>Teoria Fermiego jasno pokazuje, =
=BFe=20
                        obecno=B6=E6 rozpadu beta gwarantuje r=F3wnie=BF =
zachodzenie=20
                        tzw. <A =
href=3D"http://archiwum.wiz.pl/1996/96031804.avi"=20
                        ?960318004?>odwrotnego procesu beta</A>, czyli=20
                        oddzia=B3ywania antyneutrina z protonem wed=B3ug =

                        schematu:<BR><I>v</I><SUP>-</SUP><SUB>e</SUB> + =
p --&gt;=20
                        e<SUP>+</SUP> + n <BR>W stanie ko=F1cowym tej =
reakcji mamy=20
                        pozyton i neutron. Proces m=F3g=B3by by=E6 =
wykorzystany do=20
                        rejestracji neutrin pochodz=B1cych z rozpadu =
beta. Jednak=20
                        z teorii Fermiego wynika, =BFe =
prawdopodobie=F1stwo=20
                        oddzia=B3ywania antyneutrina z protonem jest =
wyj=B1tkowo=20
                        ma=B3e, a co za tym idzie, odwrotny proces beta =
jest=20
                        bardzo rzadki. Materia wi=EAc, cho=E6 pe=B3na =
proton=F3w, jest=20
                        dla neutrin niemal przezroczysta. Dzi=EAki swej =
niezwyk=B3ej=20
                        przenikalno=B6ci neutrino zyska=B3o miano =
cz=B1stki -=20
                        widma.</P>
                        <P class=3Dtekst>Chocia=BF samego neutrina =
zarejestrowa=E6 si=EA=20
                        nie udawa=B3o, uwa=BFna obserwacja elektron=F3w =
pochodz=B1cych z=20
                        rozpadu beta pozwoli=B3a okre=B6li=E6 jego =
w=B3asno=B6ci. Ju=BF w=20
                        1933 roku ustalono do=B6wiadczalnie, =BFe =
neutrino ma bardzo=20
                        ma=B3=B1 lub, jak fotony, zerow=B1 mas=EA i =
porusza si=EA z=20
                        pr=EAdko=B6ci=B1 =B6wiat=B3a. Podobne pomiary =
wykonywane s=B1 do=20
                        dzi=B6. Dzi=EAki nim wyznaczono niezwykle =
wy=B6rubowan=B1 g=F3rn=B1=20
                        granic=EA masy neutrina jako jedn=B1 =
stutysi=EAczn=B1 masy=20
                        elektronu, kt=F3ry jest najl=BFejsz=B1 znan=B1 =
cz=B1stk=B1=20
                        masywn=B1.</P>
                        <P class=3Dsrodtytul>POLOWANIE NA NEUTRINO </P>
                        <P class=3Dtekst>W reakcjach rozszczepienia =
j=B1der=20
                        atomowych, jakie zachodz=B1 w reaktorach, =
powstaj=B1 liczne=20
                        j=B1dra niestabilne, kt=F3re ulegaj=B1 rozpadowi =
beta.=20
                        Prowadzi to do obfitej produkcji neutrin. =
Wyliczono, =BFe=20
                        w ci=B1gu sekundy rodzi si=EA w reaktorze liczba =
neutrin tak=20
                        wielka, jak jedynka z dwudziestoma zerami. =
Maj=B1c tak=20
                        pot=EA=BFne =BCr=F3d=B3a - pierwsze reaktory =
zbudowano w latach II=20
                        wojny =B6wiatowej - mo=BFna by=B3o wreszcie =
zaobserwowa=E6=20
                        neutrina.</P>
                        <P class=3Dtekst>Frederick Reines i Clyde Cowan, =
pracuj=B1cy=20
                        w Los Alamos - miejscu powstania ameryka=F1skiej =
bomby=20
                        atomowej - przeprowadzili eksperyment, a =
w=B3a=B6ciwie dwa=20
                        kolejne, w kt=F3rych zaobserwowali neutrina =
dzi=EAki=20
                        odwrotnemu rozpadowi beta. Do=B6wiadczenie =
(patrz ryc.)=20
                        przebiega=B3o nast=EApuj=B1co: w ka=BFdej =
sekundzie miliardy=20
                        antyneutrin z reaktora trafia=B3y do zbiornika z =
wod=B1.=20
                        Tutaj, w ci=B1gu godziny, kilka z nich =
oddzia=B3ywa=B3o z=20
                        protonani, powoduj=B1c powstawanie pozyton=F3w i =
neutron=F3w.=20
                        Gdy pozyton trafi=B3 na swoj=B1 antycz=B1stk=EA, =
tzn. elektron,=20
                        nast=EApowa=B3a anihilacja obu cz=B1stek, czyli =
ich przemiana=20
                        w dwa fotony tj. kwanty =B6wiat=B3a (gamma). =
Neutrony za=B6=20
                        by=B3y absorbowane przez j=B1dra kadmu =
(wyst=EApuj=B1ce w wodzie=20
                        jako domieszka), co r=F3wnie=BF prowadzi=B3o do =
emisji=20
                        foton=F3w. A zatem, obserwacja neutrin =
polega=B3a w istocie=20
                        na rejestracji wspomnianych foton=F3w, czyli =
b=B3ysk=F3w=20
                        =B6wiat=B3a. Pomiary prowadzono zar=F3wno przy =
w=B3=B1czonym, jak=20
                        i wy=B3=B1czonym reaktorze. Chodzi=B3o o =
okre=B6lenie, ile=20
                        rejestrowanych foton=F3w pochodzi nie od =
neutrin, lecz od=20
                        promieni kosmicznych i innych zaburzaj=B1cych =
eksperyment=20
                        proces=F3w - okre=B6lanych =B3=B1cznie jako =
t=B3o, kt=F3rych nigdy=20
                        nie udaje si=EA zupe=B3nie wyeliminowa=E6. =
<BR><A=20
                        =
href=3D"http://archiwum.wiz.pl/images/duze/1996/03/96031804.GIF"=20
                        ?960318005?><IMG hspace=3D10=20
                        =
src=3D"http://archiwum.wiz.pl/images/male/1996/03/96031854.gif"=20
                        align=3Dright vspace=3D10></A><BR>Pierwszy =
eksperyment z=20
                        1953 roku wykonany przy niedu=BFym reaktorze nie =
przyni=F3s=B3=20
                        roztrzygaj=B1cych rezultat=F3w. Sygna=B3 =
pochodz=B1cy, jak=20
                        przypuszczano, od neutrin gin=B1=B3 w tle. W =
trzy lata=20
                        p=F3=BCniej wielki detektor ustawiony przy =
reaktorze w=20
                        Savannah River da=B3 w ko=F1cu jednoznacznie =
pozytywny=20
                        wynik. Obserwowana liczba neutrin zgadza=B3a =
si=EA z=20
                        teoretycznymi przewidywaniami.</P>
                        <P class=3Dtekst>Z rado=B6ci=B1 informujemy =
Pana, =BFe=20
                        zarejestrowali=B6my neutrina pochodz=B1ce z =
produkt=F3w=20
                        rozszczepienia j=B1der, obserwuj=B1c odwrotny =
rozpad beta=20
                        (...) -telegrafowali do Pauliego Frederick =
Reines i=20
                        Clyde Cowan 15 czerwca 1956 roku. Wszystko =
mo=BFe zdarzy=E6=20
                        si=EA temu, kto potrafi czeka=E6 - =
odpowiedzia=B3 Pauli. Od=20
                        napisania s=B3ynnego listu do Tybingi =
up=B3yn=EA=B3o ponad=20
                        =E6wier=E6 wieku. Frederick Reines czeka=B3 na =
sw=F3j dzie=F1=20
                        jeszcze d=B3u=BFej - prawie cztery dekady, a =
Clyde Cowan=20
                        zmar=B3, nie otrzymawszy nagrody.</P>
                        <P class=3Dsrodtytul>DRUGIE NEUTRINO </P>
                        <P class=3Dtekst>Ziemia jest nieustannie =
bombardowana=20
                        przez strumienie rozp=EAdzonych cz=B1stek, =
wspomnianych ju=BF,=20
                        promieni kosmicznych. Badania produkt=F3w =
zderze=F1 tych=20
                        cz=B1stek z j=B1drami atomowymi doprowadzi=B3y =
do licznych=20
                        odkry=E6. W 1932 roku znaleziono antycz=B1stk=EA =
elektronu,=20
                        czyli wspomniany ju=BF pozyton, za=B6 w 1947 =
roku cz=B1stk=EA=20
                        nazwan=B1 mionem i oznaczan=B1 greck=B1 liter=B1 =
<I>mi</I>. Mion=20
                        ma cechy zbli=BFone do elektronu, lecz jest =
oko=B3o 200 razy=20
                        ci=EA=BFszy. Jest r=F3wnie=BF, w =
przeciwie=F1stwie do elektronu,=20
                        nietrwa=B3y. Rozpada si=EA na elektron i jeszcze =
dwie=20
                        cz=B1stki nie rejestrowane w eksperymencie. =
Przypuszczano,=20
                        =BFe s=B1 nimi neutrina. Teoretycy sugerowali, =
=BFe mion,=20
                        podobnie jak elektron, ma swoje w=B3asne =
neutrino, czyli=20
                        neutrino mionowe. Schemat rozpadu wygl=B1da=B3by =

                        wi=EAcnast=EApuj=B1co:<BR><I>mi</I><SUP>-</SUP> =
--&gt;=20
                        e<SUP>-</SUP> + <I>v</I><SUP>-</SUP><SUB>e =
</SUB>+=20
                        <I>v<SUB>mi</SUB></I> <BR>Przed =
eksperymentatorami=20
                        stan=EA=B3o zadanie wykazania, =BFe neutrina =
elektronowe i=20
                        mionowe to r=F3=BFne cz=B1stki. W pocz=B1tku lat =

                        sze=B6=E6dziesi=B1tych wykonano do=B6wiadczenie, =
w kt=F3rym=20
                        rzeczywi=B6cie podj=EAto to wyzwanie. =
Eksperyment by=B3=20
                        mo=BFliwy dzi=EAki ogromnemu post=EApowi, jaki =
dokona=B3 si=EA w=20
                        fizyce cz=B1stek elementarnych.</P>
                        <P class=3Dtekst>Najwa=BFniejsz=B1 metod=B1 =
badawcz=B1 w tej=20
                        dziedzinie jest obserwacja produkt=F3w zderze=F1 =

                        rozp=EAdzonych cz=B1stek. Pocz=B1tkowo jedynie =
promienie=20
                        kosmiczne dostarcza=B3y cz=B1stek o dostatecznie =
du=BFych=20
                        energiach. Jednak z czasem akceleratory =
-urz=B1dzenia, w=20
                        kt=F3rych cz=B1stki s=B1 przy=B6pieszane za =
pomoc=B1 pola=20
                        elektromagnetycznego, zacz=EA=B3y przejmowa=E6 =
t=EA rol=EA.=20
                        Pierwsze, z prze=B3omu lat dwudziestych i =
trzydziestych,=20
                        by=B3y zaledwie kilkumetrowej wielko=B6ci. =
Nast=EApne wymaga=B3y=20
                        ju=BF wielkich hal. Aby osi=B1ga=E6 jeszcze =
wi=EAksze energie=20
                        zderze=F1, budowano coraz pot=EA=BFniejsze =
urz=B1dzenia, kt=F3re=20
                        osi=B1gn=EA=B3y w ko=F1cu kilometrowe rozmiary. =
Ka=BFda kolejna=20
                        generacja akcelerator=F3w umo=BFliwia=B3a nowe =
odkrycia. W=20
                        latach pi=EA=E6dziesi=B1tych dysponowano ju=BF =
akceleratorem,=20
                        wybudowanym na Long Island w okolicach Nowego =
Jorku,=20
                        dzi=EAki kt=F3remu otrzymano intensywny =
strumie=F1 mion=F3w.=20
                        Mo=BFna wi=EAc by=B3o wykaza=E6 odmienno=B6=E6 =
neutrin elektronowych=20
                        i mionowych.</P>
                        <P class=3Dtekst>Neutrino mionowe, =
oddzia=B3ywuj=B1c z=20
                        protonem, daje neutron oraz mion, natomiast =
neutriono=20
                        elektronowe neutron i elektron. Mog=B1 zatem =
zachodzi=E6=20
                        reakcje:<BR><I>v<SUB>mi</SUB></I> + p --&gt;=20
                        <I>mi</I><SUP>-</SUP> + n <I>v</I><SUB>e</SUB> + =
p=20
                        --&gt; e<SUP>-</SUP> + n <BR>Je=B6li oba =
neutrina mionowe=20
                        i elektronowe nie r=F3=BFni=B1 si=EA od siebie, =
to neutrino (nie=20
                        antyneutrino) pochodz=B1ce z rozpadu mionu =
b=EAdzie=20
                        inicjowa=E6 obie reakcje. Je=B6li natomiast =
neutrino mionowe=20
                        to odmienna od elektronowego cz=B1stka, =
b=EAdziemy=20
                        obserwowa=E6 tylko miony.</P>
                        <P class=3Dtekst>Poniewa=BF prawdopodobie=F1stwo =
oddzia=B3ywania=20
                        neutrina jest - jak ju=BF pisa=B3em- niezwykle =
ma=B3e, g=B3=F3wnym=20
                        problemem w przeprowadzeniu do=B6wiadczenia =
by=B3o=20
                        odizolowanie detektora od promieniowania =
kosmicznego i=20
                        wszelkich innych zaburze=F1 zewn=EAtrznych. Jako =
os=B3ony=20
                        wykorzystano, w tym najwi=EAkszym eksperymencie =
owych=20
                        czas=F3w, setki ton stali pochodz=B1ce z =
poci=EAtego na=20
                        kawa=B3ki ameryka=F1skiego okr=EAtu Missouri. W =
rezultacie=20
                        o=B6miomiesi=EAcznych pomiar=F3w =
przeprowadzonych w 1961 roku=20
                        zarejestrowano 29 mion=F3w i =BFadnego =
elektronu. Wykazano=20
                        zatem istnienie dw=F3ch odmiennych typ=F3w =
neutrina, a co za=20
                        tym idzie, dw=F3ch typ=F3w zachowywanego =
=B3adunku=20
                        leptonowego.</P>
                        <P class=3Dtekst>Za przeprowadzenie tego =
eksperymentu=20
                        przyznano w 1988 roku Nagrod=EA Nobla L.M. =
Ledermanowi, M.=20
                        Schwartzowi i J. Steinbergerowi. Pierwsza =
obserwacja=20
                        neutrina pozostawa=B3a za=B6 nadal nie =
nagrodzona.</P>
                        <P class=3Dsrodtytul>DRUGIE I TRZECIE =
<BR>POKOLENIE </P>
                        <P class=3Dtekst>Wspomnia=B3em ju=BF, =BFe =
=B6wiatem cz=B1stek=20
                        elementarnych rz=B1dz=B1 si=B3y - =
elektromagnetyczne, s=B3abe i=20
                        silne. Obiekty elementarne podzielono na dwie =
grupy,=20
                        wedle oddzia=B3ywa=F1, jakim podlegaj=B1. =
Pierwsz=B1 stanowi=B1=20
                        oddzia=B3ywuj=B1ce s=B3abo leptony, do kt=F3rych =
nale=BF=B1 pary:=20
                        elektron z neutrinem elektronowym i mion z =
neutrinem=20
                        mionowym. Elektron oraz mion, jak i wszystkie =
cz=B1stki=20
                        obdarzone =B3adunkiem elektrycznym, podlegaj=B1 =
r=F3wnie=BF=20
                        si=B3om elektromagnetycznym. Druga grupa to =
kwarki, kt=F3re=20
                        oddzia=B3ywuj=B1 s=B3abo i elektromagnetycznie, =
a tak=BFe=20
                        silnie. To ostatnie oddzia=B3ywanie sprawia, =
=BFe kwarki=20
                        wi=B1=BF=B1 si=EA w protony i neutrony; stanowi =
r=F3wnie=BF o ich=20
                        szczeg=F3lnej roli w strukturze mikro=B6wiata. =
Pocz=B1tkowo=20
                        znano tylko trzy typy kwark=F3w oznaczane =
literami u, d i=20
                        s. Kiedy w roku 1974 odkryto czwarty kwark c, =
ujawni=B3a=20
                        si=EA g=B3=EAboka symetria mi=EAdzy kwarkami a =
leptonami.=20
                        Okaza=B3o si=EA mianowicie, =BFe kwarki, =
podobnie jak leptony,=20
                        wyst=EApuj=B1 parami (u, d) oraz (c, s). Co =
wi=EAcej, ka=BFdej=20
                        parze lepton=F3w odpowiada para kwark=F3w i =
razem stanowi=B1=20
                        pokolenie. Do pierwszego pokolenia nale=BF=B1 =
kwarki (u, d)=20
                        i leptony (e,<I>v</I><SUB>e</SUB>), do drugiego =
za=B6 (c,=20
                        s) i (<I>mi</I>,<I>v<SUB>mi</SUB></I> ). Opisana =

                        symetria zapewnia matematyczn=B1 sp=F3jno=B6=E6 =
teoretycznego=20
                        modelu opisuj=B1cego zjawiska mikro=B6wiata, =
kt=F3ry przyj=EAto=20
                        nazywa=E6 Modelem Standardowym. (Wi=EAcej =
informacji o=20
                        kwarkach i Modelu Standardowym znajdzie =
Czytelnik w=20
                        artykule <I>Sz=F3sty kwark</I>, "Wi=AF", nr =
7/1994).</P>
                        <P class=3Dtekst>W tym samym mniej wi=EAcej =
czasie, gdy=20
                        odkryto czwarty kwark i porz=B1dkowa=B3 si=EA =
obraz=20
                        mikro=B6wiata, w Stanford w Kalifornii =
rozpocz=B1=B3 prac=EA=20
                        nowy akcelerator, w kt=F3rym uzyskano =
rekordow=B1 energi=EA=20
                        zderze=F1 elektron=F3w i pozyton=F3w. W=B6r=F3d =
przebadanych=20
                        tysi=EAcy takich zderze=F1 znaleziono 24 =
przypadki, w=20
                        kt=F3rych zarejestrowano jako produkty reakcji =
elektron i=20
                        antymion albo pozyton i mion. Mo=BFna to =
zapisa=E6=20
                        jako<BR>e<SUP>+</SUP> + e<SUP>-</SUP> --&gt; e + =

                        <I>mi</I> + X <BR>gdzie X oznacza co najmniej =
dwie=20
                        neutralne cz=B1stki, kt=F3re nie zostawia=B3y =
=BFadnych =B6lad=F3w w=20
                        detektorze. Szczeg=F3=B3owa analiza tych =
przypadk=F3w=20
                        wykaza=B3a, =BFe w zderzeniach elektron=F3w i =
pozyton=F3w=20
                        produkowana by=B3a nowa cz=B1stka, nazwana =
leptonem tau i=20
                        oznaczana greck=B1 liter=B1 <I>tau</I>. =
Dok=B3adniej,=20
                        powstawa=B3a para: cz=B1stka i antycz=B1stka=20
                        tj.<BR>e<SUP>+</SUP> + e<SUP>-</SUP> --&gt;=20
                        <I>tau</I><SUP>+</SUP> + <I>tau</I><SUP>-</SUP> =
<BR><A=20
                        =
href=3D"http://archiwum.wiz.pl/1996/96031801.avi"=20
                        ?960318006?>Lepton tau</A>, nale=BFy do tej =
samej grupy co=20
                        elektron i mion, ma wi=EAc jako partnera =
odpowiednie=20
                        neutrino (<I>*</I><SUB>*</SUB>) i rozpada si=EA=20
                        nast=EApuj=B1co<BR><I>tau</I> --&gt; l +=20
                        <I>v</I><SUP>-</SUP><SUB>l</SUB> +=20
                        <I>v<SUB>tau</SUB></I> <BR>gdzie l oznacza =
elektron lub=20
                        mion. Sekwencja procesu produkcji i rozpadu =
cz=B1stek tau=20
                        dawa=B3a wspomniane dwadzie=B6cia cztery =
przypadki (ryc.=20
                        poni=BFej).</P>
                        <P class=3Ddodatek><A=20
                        =
href=3D"http://archiwum.wiz.pl/images/duze/1996/03/96031801.JPG"=20
                        ?960318007?><IMG hspace=3D10=20
                        =
src=3D"http://archiwum.wiz.pl/images/male/1996/03/96031851.JPG"=20
                        align=3Dright vspace=3D10></A>P=B3etwonurek w =
detektorze IMB z=20
                        eksperymentu, kt=F3rym kierowa=B3 Frederick =
Reines. (Skr=F3t=20
                        IMB pochodzi od Irvine, Michigan, Brookhaven -=20
                        miejscowo=B6ci, z jakich pochodz=B1 g=B3=F3wni =
tw=F3rcy=20
                        urz=B1dzenia). Detektor jest zbiornikiem =
wype=B3nionym 8000=20
                        ton doskonale czystej wody, umieszczonym 600 m =
pod=20
                        jeziorem Erie, w kopalni soli, w okolicach =
Cleveland w=20
                        USA. Widoczne urz=B1dzenia rejestruj=B1 b=B3yski =
wywo=B3ywane=20
                        przez ewentualny rozpad protonu b=B1d=BC =
neutrina=20
                        docieraj=B1ce z kosmosu </P>
                        <P class=3Dtekst>Odkrycie leptonu tau, a=BF 3500 =
razy=20
                        ci=EA=BFszego od elektronu, dokona=B3 liczny =
zesp=F3=B3 fizyk=F3w=20
                        kierowany przez ubieg=B3orocznego noblist=EA - =
Martina L.=20
                        Perla. Cz=B1stka ta, nazwana od pierwszej litery =
greckiego=20
                        s=B3owa triton - trzeci, zwiastowa=B3a istnienie =
trzeciego=20
                        pokolenia kwark=F3w. Rzeczywi=B6cie, ju=BF w =
roku 1975 odkryto=20
                        pi=B1ty kwark oznaczany liter=B1 b. Natomiast =
kwark sz=F3sty t=20
                        pozostawa=B3 nieuchwytny przez prawie lat 20. =
Zosta=B3=20
                        zaobserwowany dopiero w 1994 roku. W ten =
spos=F3b=20
                        znaleziono wszystkich przedstawicieli=20
                        trzeciegopokolenia.</P>
                        <P class=3Dsrodtytul>CZY TO JU=AF WSZYSTKO? </P>
                        <P class=3Dtekst>Model Standardowy jest tak =
skonstruowany,=20
                        =BFe kwarki i leptony musz=B1 wyst=EApowa=E6 =
parami, a liczby=20
                        par kwark=F3w i lepton=F3w powinny by=E6 sobie =
r=F3wne. Model=20
                        natomiast nie ogranicza liczby pokole=F1. =
Do=B6wiadczalnie=20
                        jednak wykazano, =BFe w przyrodzie s=B1 tylko =
trzy=20
                        pokolenia.</P>
                        <P class=3Dtekst>W Europejskim Laboratorium =
Cz=B1stek=20
                        Elementarnych (CERN) pod Genew=B1 badano na =
pocz=B1tku lat=20
                        dziewi=EA=E6dziesi=B1tych rozpady neutralnej =
cz=B1stki znanej=20
                        jako Z<SUP>0</SUP>. Mo=BFe ona rozpada=E6 si=EA =
na par=EA:=20
                        neutrino i antyneutrino,tzn.<BR>Z<SUP>0</SUP> =
--&gt;=20
                        <I>v</I><SUB>l</SUB> + =
<I>v</I><SUP>-</SUP><SUB>l</SUB>=20
                        <BR>gdzie l oznacza dowolny lepton. Im wi=EAksza =
jest=20
                        liczba neutrin, kt=F3rych nie udaje si=EA =
rejestrowa=E6, tym=20
                        wi=EAcej mo=BFliwych kana=B3=F3w rozpadu, a =
zatem kr=F3tszy czas=20
                        =BFycia cz=B1stki Z<SUP>0</SUP>. Liczb=EA =
typ=F3w neutrin=20
                        okre=B6lono zmierzywszy w=B3a=B6nie ten czas =
=BFycia. Pomiar=20
                        przypomina wi=EAc dociekania nad liczb=B1 dziur =
w wiadrze, z=20
                        kt=F3rego ucieka woda. (Wiadro z wod=B1 =
odpowiada cz=B1stce=20
                        Z<SUP>0</SUP>, za=B6 dziury neutrinom.) Je=B6li =
znamy=20
                        =B6rednic=EA otworu, to mo=BFemy oceni=E6, ile =
wody przeze=F1=20
                        wyp=B3ywa w jednostce czasu. Mierz=B1c wi=EAc =
czas, w jakim=20
                        woda wycieknie z wiadra, mo=BFemy wyznaczy=E6 =
liczb=EA=20
                        dziur.</P>
                        <P class=3Dtekst>Okazuje si=EA, =BFe =
astrofizyczne rozwa=BFania=20
                        r=F3wnie=BF sugeruj=B1 istnienie trzech =
pokole=F1 kwark=F3w i=20
                        lepton=F3w. Procesy nukleosynetzy, czyli =
powstawania=20
                        ci=EA=BFszych j=B1der z wodoru =
wype=B3niaj=B1cego Wszech=B6wiat, s=B1=20
                        czu=B3e na liczb=EA typ=F3w neutrin. Gdyby =
liczba ta by=B3a inna=20
                        ni=BF trzy, sk=B3ad chemiczny =B6wiata by=B3by =
odmienny od tego,=20
                        jaki obserwujemy. <BR><A=20
                        =
href=3D"http://archiwum.wiz.pl/images/duze/1996/03/96031805.GIF"=20
                        ?960318008?><IMG hspace=3D10=20
                        =
src=3D"http://archiwum.wiz.pl/images/male/1996/03/96031855.gif"=20
                        align=3Dright vspace=3D10></A><BR>Jak wida=E6 =
mamy wa=BFkie i=20
                        niezale=BFne od siebie argumenty, aby =
s=B1dzi=E6, =BFe=20
                        poznali=B6my ju=BF wszystkie istniej=B1ce w =
przyrodzie=20
                        najprostsze cz=B1stki materii.Leptonowo-kwarkowa =
uk=B3adanka=20
                        jest wi=EAc kompletna.</P>
                        <P class=3Dsrodtytul>CO DALEJ? </P>
                        <P class=3Dtekst>Reines i Cowan rozpocz=EAli =
nast=EApuj=B1co=20
                        doniesienie sprzed lat o zaobserwowaniu =
neutrina: Ka=BFde=20
                        fizyczne odkrycie poszerza nasz=B1 wiedz=EA i =
pog=B3=EAbia=20
                        rozumienie =B6wiata. Bywaj=B1 jednak odkrycia, =
kt=F3re=20
                        prowadz=B1 do nowych pyta=F1, bardziej =
fundamentalnych ni=BF=20
                        te, na kt=F3re zdo=B3a=B3y odpowiedzie=E6. =
S=B3owa te doskonale=20
                        pasuj=B1 do poszukiwa=F1, kt=F3re zaowocowa=B3y =
sformu=B3owaniem=20
                        Modelu Standardowego, b=EAd=B1cego =
najpe=B3niejszym wyrazem=20
                        naszej wiedzy o najprostszych strukturach =
materii. Wszak=20
                        wiemy, =BFe Wszech=B6wiat tworz=B1 trzy =
pokolenia kwark=F3w i=20
                        lepton=F3w, nie mamy jednak poj=EAcia dlaczego =
w=B3a=B6nie trzy.=20
                        Na to i podobne pytania mo=BFe kiedy=B6 odpowie =
teoria zwana=20
                        Wielk=B1 Unifikacj=B1, kt=F3ra wch=B3onie Model =
Standardowy.=20
                        Fizycy pr=F3buj=B1 stworzy=E6 tak=B1 teori=EA; =
istnieje ju=BF kilka=20
                        jej wariant=F3w. Jednak wyb=F3r w=B3a=B6ciwego =
kierunku=20
                        poszukiwa=F1 wymaga =
wskaz=F3wekdo=B6wiadczalnych.</P>
                        <P class=3Dtekst>Zgodnie z Modelem Standardowym =
proton=20
                        jest cz=B1stk=B1 stabiln=B1, czyli ma =
niesko=F1czony czas =BFycia,=20
                        nie rozpada si=EA. Natomiast r=F3=BFne wersje =
Wielkiej=20
                        Unifikacji sugeruj=B1, =BFe czas =BFycia =
protonu, cho=E6 bardzo=20
                        d=B3ugi, jest jednak sko=F1czony. Frederick =
Reines przez=20
                        wiele lat prowadzi=B3 pionierskie badania =
zmierzaj=B1ce do=20
                        wyznaczenia tej wielko=B6ci.</P>
                        <P class=3Dtekst>Do=B6wiadczenie polega=B3o na =
obserwowaniu,=20
                        czy w zbiorniku zawieraj=B1cym tysi=B1ce ton =
doskonale=20
                        czystej wody nie nast=B1pi b=B3ysk wywo=B3any =
rozpadni=EAciem=20
                        si=EA protonu - jednego z bilion=F3w =
tworz=B1cych wod=EA. Tak=20
                        jak i w przypadku eksperyment=F3w neutrinowych, =
g=B3=F3wny=20
                        problem polega=B3 na wyeliminowaniu t=B3a od =
promieniowania=20
                        kosmicznego. Z tego powodu zbiornik z wod=B1 =
umieszczono=20
                        g=B3=EAboko pod ziemi=B1 w kopalni soli. =
Dociera=B3y tutaj=20
                        niemal wy=B3=B1cznie kosmiczne neutrina. =
(Dzi=EAki temu=20
                        zaobserwowano neutrina pochodz=B1ce z wybuchu =
supernowej w=20
                        Wielkim Ob=B3oku Magellana, jaki zdarzy=B3 si=EA =
w roku 1987.)=20
                        Eksperyment nie stwierdzi=B3 ani jednego =
przypadku rozpadu=20
                        protonu. Wyznaczono jedynie doln=B1 granic=EA =
jego d=B3ugo=B6ci=20
                        =BFycia. Proton =BFyje co najmniej =
10<SUP>30</SUP> lat.=20
                        Eliminuje to niemal wszystkie znane warianty =
Wielkiej=20
                        Unifikacji, kt=F3re sugerowa=B3y kr=F3tsze =
czasy. By=E6 mo=BFe=20
                        nast=EApny eksperyment, zdolny rejestrowa=E6 =
jeszcze rzadsze=20
                        procesy, udowodni, =BFe proton jednak si=EA =
rozpada.=20
                        Teoretycy otrzymaj=B1 wtedy drogocenn=B1 =
wskaz=F3wk=EA na drodze=20
                        ku wymarzonej Og=F3lnej Teorii Wszystkiego, =
kt=F3ra wska=BFe=20
                        jedno pra=BCr=F3d=B3o wszystkich typ=F3w =
oddzia=B3ywa=F1, czasu i=20
                        przestrzeni.</P>
                        <P class=3Dtekst><A name=3DFRED></A><A=20
                        =
href=3D"http://archiwum.wiz.pl/images/duze/1996/03/96031803.JPG"=20
                        ?960318009?><IMG hspace=3D10=20
                        =
src=3D"http://archiwum.wiz.pl/images/male/1996/03/96031853.JPG"=20
                        align=3Dright vspace=3D10></A></P>
                        <P class=3Dsrodtytul>FREDERICK REINES</P>
                        <P class=3Dtekst>Urodzi=B3 si=EA w roku 1918 w =
Paterson w New=20
                        Jersey. Jego rodzice pochodzili z =
Bia=B3egostoku. Doktorat=20
                        uzyska=B3 w roku 1944 na Uniwersytecie =
Nowojorskim.=20
                        P=F3=BCniej pracowa=B3 w Los Alamos, a obecnie =
jest profesorem=20
                        na Uniwersytecie Kalifornijskim w Irvine. Jest =
cz=B3onkiem=20
                        ameryka=F1skiej i rosyjskiej Akademii Nauk. Do =
jego=20
                        bliskich wsp=F3=B3pracownik=F3w nale=BFy od lat =
Danuta=20
                        Kie=B3czewska z Uniwersytetu Warszawskiego. =
Profesor=20
                        Reines my=B6la=B3 w m=B3odo=B6ci o karierze =
=B6piewaka -=20
                        wyst=EApowa=B3 nawet w operze w Cleveland. Jest =
r=F3wnie=BF=20
                        utalentowany literacko. Ma =BFon=EA i dwoje=20
                        dzieci.<BR><BR><A=20
                        =
href=3D"http://archiwum.wiz.pl/1996/96031800.asp#TOP"=20
                        ?9603180010?>Do pocz=B1tku artyku=B3u...</A></P>
                        <P class=3Dtekst><A name=3DMARTI></A></P>
                        <P align=3Dright><A=20
                        =
href=3D"http://archiwum.wiz.pl/images/duze/1996/03/96031802.JPG"=20
                        ?9603180011?><IMG hspace=3D10=20
                        =
src=3D"http://archiwum.wiz.pl/images/male/1996/03/96031852.JPG"=20
                        align=3Dright vspace=3D10></A></P>
                        <P class=3Dsrodtytul>MARTIN L. PERL</P>
                        <P class=3Dtekst>Urodzi=B3 si=EA w roku 1927 w =
Nowym Jorku.=20
                        Doktorat uzyska=B3 na Uniwersytecie Kolumbijskim =
w roku=20
                        1955. Jest cz=B3onkiem ameryka=F1skiej Akademii =
Nauk.=20
                        Pracuje na Uniwersytecie w Stanford, w=20
                        Kalifornii.<BR><BR><A=20
                        =
href=3D"http://archiwum.wiz.pl/1996/96031800.asp#TOP"=20
                        ?9603180012?>Do pocz=B1tku artyku=B3u...</A></P>
                        <P class=3Danotka>Dr hab. STANIS=A3AW =
MR=D3WCZY=D1SKI pracuje w=20
                        Instytucie Problem=F3w J=B1drowych im. Andrzeja =
So=B3tana w=20
                        =
Warszawie.</P></TD></TR></TBODY></TABLE></TD></TR>
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------=_NextPart_000_000F_01C9F299.AFDE0150
Content-Type: text/css;
	charset="iso-8859-2"
Content-Transfer-Encoding: quoted-printable
Content-Location: http://archiwum.wiz.pl/css/css.css

BODY {
	MARGIN: 20px 0px; BACKGROUND-COLOR: skyblue
}
BODY.bd {
	BORDER-RIGHT: #f8ead0 2px inset; BORDER-TOP: #f8ead0 2px inset; =
BORDER-LEFT: #f8ead0 2px inset; BORDER-BOTTOM: #f8ead0 2px inset
}
.menu {
	PADDING-RIGHT: 20px; PADDING-LEFT: 0px; FONT-SIZE: 11px; FLOAT: right; =
PADDING-BOTTOM: 0px; CURSOR: pointer; COLOR: #844139; LINE-HEIGHT: 17px; =
PADDING-TOP: 3px; FONT-FAMILY: "Verdana", sans-serif; TEXT-ALIGN: right
}
.menu_print {
	TEXT-DECORATION: underline
}
.stopka {
	PADDING-RIGHT: 20px; PADDING-LEFT: 20px; FONT-SIZE: 11px; =
PADDING-BOTTOM: 20px; COLOR: #844139; LINE-HEIGHT: 20px; PADDING-TOP: =
20px; FONT-FAMILY: "Verdana", sans-serif; TEXT-ALIGN: center
}
.hr_footer {
	MARGIN: 0px 0px 10px; COLOR: silver; HEIGHT: 3px
}
.hr_header {
	MARGIN: 5px 0px 10px; COLOR: silver; HEIGHT: 3px
}
.tekst {
	FONT-SIZE: 75%; COLOR: black; LINE-HEIGHT: 150%; FONT-FAMILY: =
"Verdana", sans-serif
}
.tekst_2 {
	FONT-SIZE: 75%; COLOR: black; LINE-HEIGHT: 130%; FONT-FAMILY: =
"Verdana", sans-serif
}
.szukacz_logo {
	PADDING-RIGHT: 0px; PADDING-LEFT: 0px; PADDING-BOTTOM: 0px; MARGIN: 0px =
5px 0px 20px; COLOR: black; PADDING-TOP: 0px; FONT-FAMILY: "Verdana", =
sans-serif
}
.szukacz_help {
	PADDING-RIGHT: 0px; PADDING-LEFT: 0px; FONT-SIZE: 10px; PADDING-BOTTOM: =
0px; MARGIN: 0px 0px 1px; VERTICAL-ALIGN: top; COLOR: black; =
LINE-HEIGHT: 8px; PADDING-TOP: 0px; FONT-FAMILY: "Verdana", sans-serif; =
TEXT-ALIGN: left
}
.szukacz_query {
	PADDING-RIGHT: 5px; PADDING-LEFT: 5px; FONT-SIZE: 11px; PADDING-BOTTOM: =
0px; MARGIN: 0px; VERTICAL-ALIGN: bottom; WIDTH: 180px; COLOR: black; =
PADDING-TOP: 0px; FONT-FAMILY: "Verdana", sans-serif; HEIGHT: 20px
}
.szukacz_submit {
	PADDING-RIGHT: 2px; PADDING-LEFT: 2px; FONT-SIZE: 11px; PADDING-BOTTOM: =
0px; MARGIN: 0px 0px 2px; VERTICAL-ALIGN: bottom; COLOR: black; =
PADDING-TOP: 0px; FONT-FAMILY: "Verdana", sans-serif; HEIGHT: 20px
}
.szukacz_radio {
	FONT-SIZE: 10px; COLOR: black; FONT-FAMILY: "Verdana", sans-serif
}
A:hover {
	COLOR: gray
}
.glowna {
	FONT-WEIGHT: normal; FONT-SIZE: 13px; FONT-FAMILY: "Verdana", =
Sans-Serif
}
.qtext {
	FONT-SIZE: 12px; BORDER-LEFT-COLOR: #f7ead0; BORDER-BOTTOM-COLOR: =
#f7ead0; COLOR: #000000; BORDER-TOP-COLOR: #f7ead0; BACKGROUND-COLOR: =
#f7ead0; BORDER-RIGHT-COLOR: #f7ead0
}
.qbutton {
	BORDER-RIGHT: #f8ead0 0px; BORDER-TOP: #f8ead0 0px; BORDER-LEFT: =
#f8ead0 0px; BORDER-BOTTOM: #f8ead0 0px; BACKGROUND-COLOR: #f8ead0
}
.infield {
	BORDER-RIGHT: #f8ead0 2px outset; BORDER-TOP: #f8ead0 2px outset; =
BORDER-LEFT: #f8ead0 2px outset; BORDER-BOTTOM: #f8ead0 2px outset; =
BACKGROUND-COLOR: #f8ead0
}
A.mc {
	FONT-SIZE: 11px; COLOR: #000000; FONT-FAMILY: "Verdana", Sans-Serif; =
TEXT-DECORATION: none
}
IMG.mc {
	BORDER-LEFT-COLOR: #000000; BORDER-BOTTOM-COLOR: #000000; =
BORDER-TOP-COLOR: #000000; BORDER-RIGHT-COLOR: #000000
}
.sel {
	FONT-SIZE: 14px; OVERFLOW: scroll; WIDTH: 552px; FONT-FAMILY: =
"Verdana", Sans-Serif; HEIGHT: 329px; BACKGROUND-COLOR: #f8ead0
}
.fr {
	BORDER-LEFT-COLOR: #f8ead0; BORDER-BOTTOM-COLOR: #f8ead0; WIDTH: 552px; =
BORDER-TOP-COLOR: #f8ead0; HEIGHT: 329px; BORDER-RIGHT-COLOR: #f8ead0
}
.left {
	WIDTH: 20px; HEIGHT: 329px
}
.red {
	FONT-SIZE: 13px; FONT-FAMILY: "Verdana", Sans-Serif
}
A {
	COLOR: #844139; FONT-FAMILY: "Verdana", Sans-Serif
}
A IMG {
	BORDER-LEFT-COLOR: #844139; BORDER-BOTTOM-COLOR: #844139; =
BORDER-TOP-COLOR: #844139; BORDER-RIGHT-COLOR: #844139
}
.aut {
	FONT-SIZE: 12px; COLOR: #844139; FONT-FAMILY: "Verdana", Sans-Serif
}
.naut {
	FONT-WEIGHT: bold; FONT-SIZE: 15px; PADDING-BOTTOM: 20px; COLOR: =
#000000; FONT-FAMILY: "Verdana", Sans-Serif
}
.tytulartykulu {
	FONT-SIZE: 13px; CURSOR: pointer; COLOR: #844139; FONT-FAMILY: =
"Verdana", Sans-Serif; TEXT-DECORATION: underline
}
.dataartykulu {
	FONT-SIZE: 11px; COLOR: #000000; FONT-STYLE: italic; FONT-FAMILY: =
"Verdana", Sans-Serif
}
.autorartykulu {
	FONT-SIZE: 11px; COLOR: #000000; FONT-STYLE: italic; FONT-FAMILY: =
"Verdana", Sans-Serif
}
.notkaartykulu {
	PADDING-RIGHT: 15px; PADDING-LEFT: 15px; FONT-SIZE: 11px; =
PADDING-BOTTOM: 15px; COLOR: #000000; PADDING-TOP: 2px; FONT-FAMILY: =
"Verdana", Sans-Serif; TEXT-ALIGN: justify
}
.grupa {
	FONT-SIZE: 14px; COLOR: #844139; FONT-FAMILY: "Verdana", Sans-Serif
}
.podgrupa {
	PADDING-LEFT: 15px; FONT-SIZE: 12px; COLOR: #844139; FONT-FAMILY: =
"Verdana", Sans-Serif
}
.autor {
	FONT-WEIGHT: bold; FONT-SIZE: 79%; COLOR: black; LINE-HEIGHT: 120%; =
FONT-FAMILY: "Verdana", sans-serif
}
.tytul {
	FONT-WEIGHT: bold; FONT-SIZE: 112%; COLOR: #d2691c; LINE-HEIGHT: 133%; =
FONT-FAMILY: "Verdana", sans-serif
}
.okladkapodpis {
	FONT-SIZE: 75%; COLOR: gray; LINE-HEIGHT: 120%; FONT-FAMILY: "Verdana", =
sans-serif
}
P.tekst {
	FONT-SIZE: 80%; COLOR: black; LINE-HEIGHT: 160%; FONT-FAMILY: =
"Verdana", sans-serif
}
P.tekst LI {
	FONT-SIZE: 80%; COLOR: black; LINE-HEIGHT: 160%; FONT-FAMILY: =
"Verdana", sans-serif
}
P A {
	FONT-SIZE: 100%; COLOR: #844139; FONT-FAMILY: "Verdana", Sans-Serif
}
UL A {
	FONT-SIZE: 100%; COLOR: #844139; FONT-FAMILY: "Verdana", Sans-Serif
}
OL A {
	FONT-SIZE: 100%; COLOR: #844139; FONT-FAMILY: "Verdana", Sans-Serif
}
OL.tekst {
	FONT-SIZE: 80%; COLOR: black; LINE-HEIGHT: 160%; FONT-FAMILY: =
"Verdana", sans-serif
}
UL.tekst {
	FONT-SIZE: 80%; COLOR: black; LINE-HEIGHT: 160%; FONT-FAMILY: =
"Verdana", sans-serif
}
P.wstep {
	FONT-WEIGHT: bold; FONT-SIZE: 84%; COLOR: black; LINE-HEIGHT: 160%; =
FONT-FAMILY: "Verdana", sans-serif
}
P.srodtytul {
	PADDING-LEFT: 10px; FONT-WEIGHT: bold; FONT-SIZE: 82%; COLOR: #000000; =
LINE-HEIGHT: 180%; FONT-FAMILY: "Verdana", sans-serif; BACKGROUND-COLOR: =
#ffcf9c
}
P.anotka {
	FONT-SIZE: 80%; COLOR: gray; LINE-HEIGHT: 160%; FONT-FAMILY: "Verdana", =
sans-serif
}
.dodatektytul {
	PADDING-LEFT: 10px; FONT-WEIGHT: bold; FONT-SIZE: 82%; COLOR: #d2691e; =
LINE-HEIGHT: 180%; FONT-FAMILY: "Verdana", sans-serif; BACKGROUND-COLOR: =
#ffcf9c
}
P.dodatek {
	FONT-SIZE: 80%; COLOR: #674357; LINE-HEIGHT: 160%; FONT-FAMILY: =
"Verdana", sans-serif
}
OL.dodatek {
	FONT-SIZE: 80%; COLOR: #674357; LINE-HEIGHT: 160%; FONT-FAMILY: =
"Verdana", sans-serif
}
UL.dodatek {
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}
P.przypis {
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TD.przypis {
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"Verdana", sans-serif
}
A.fpspan {
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}

------=_NextPart_000_000F_01C9F299.AFDE0150
Content-Type: application/octet-stream
Content-Transfer-Encoding: quoted-printable
Content-Location: http://analytics.live.com/Analytics/msAnalytics.js

// Copyright 2007 Microsoft Corporation.  All rights reserved.
// Build: 3525
function $clean(data){switch(typeof(data)){case"string":return =
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$sync(aqnt){if(location.protocol.indexOf("http")<0||window.navigator.user=
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true;};List.prototype.Find=3Dfunction(searchKey){var =
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end=3Dthis.Last;if(!$assertValue(start)||!$assertValue(end)){return =
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pe.length=3D=3D1){linkUrlType=3DlinkType;} =
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List();this.Taxonomy.Add("Links","lnk",ListNodeType.Variable);} =
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MicrosoftAnalytics.prototype.OnTrackLink=3Dfunction(evt){var =
srcElement=3Dtypeof(event)!=3D"undefined"&&$assertValue(event)?event.srcE=
lement:this;if(srcElement.tagName!=3D"A"){do{srcElement=3D$assertValue(sr=
cElement.parentElement)?srcElement.parentElement:srcElement.parentNode;} =
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loggingObject=3DsrcElement.LoggingObject;if(loggingObject=3D=3Dnull){retu=
rn true;} var urlPath=3DsrcElement.pathname;var =
dotIndex=3DurlPath.lastIndexOf(".");var =
foundMatch=3Dfalse;if(dotIndex>=3D0){var =
fileExt=3DurlPath.substring(dotIndex+1);if(srcElement.LoggingObject.Exten=
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if(!foundMatch&&srcElement.host.indexOf(location.host)>=3D0){return =
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eventPayload=3DloggingObject.SubmitPayload(PayloadType.Link);if($assertVa=
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if(loggingObject.EnableLinkTimeout=3D=3Dtrue){loggingObject.PauseLink(log=
gingObject.LinkTimeout);} return =
true;};MicrosoftAnalytics.prototype.GetUserIdentity=3Dfunction(){var =
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return =
userId;};MicrosoftAnalytics.prototype.SetUserIdentity=3Dfunction(userId){=
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nString=3D"; domain=3D"+this.CookieDomain+";";} else{var =
hostName=3Dlocation.host;if($assertType(hostName,"string")&&hostName.leng=
th>0){if(hostName.substring(0,4)=3D=3D"www."){domainString=3D"; =
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userIdCookie=3Dthis.CookieName+"=3D"+userId+domainString+"; =
expires=3DFri, 01-Jan-2021 00:00:00 GMT; =
path=3D/;";document.cookie=3DuserIdCookie;var =
newUserId=3Dthis.ParseUserIdentity();return =
newUserId.length>0;};MicrosoftAnalytics.prototype.ParseUserIdentity=3Dfun=
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cookieString=3Ddocument.cookie.toString();var expRegex=3Dnew =
RegExp(this.IdentityRegex);var =
regexMatch=3DexpRegex.exec(cookieString);if(regexMatch){userId=3DregexMat=
ch[2];} return =
userId;};MicrosoftAnalytics.prototype.GenerateUserIdentity=3Dfunction(){v=
ar vals=3Dnew =
Array('0','1','2','3','4','5','6','7','8','9','a','b','c','d','e','f');va=
r key=3D"";var last=3D-1;var idx=3D-1;for(var =
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x=3DMath.floor(x%256);key+=3D'_'+vals[Math.floor(x/16)]+vals[x%16];var =
s=3Dnew =
Date();x=3Ds.getTime()%16777216;x=3Dx.toString();while(x.length<8)x=3D'0'=
+x;{key+=3D'_'+x;} return =
key;};MicrosoftAnalytics.prototype.SubmitPayload=3Dfunction(payloadType){=
if(!$assertType(this.ProfileId,"string")||this.ProfileId.length=3D=3D0){r=
eturn null;} if(location.protocol.indexOf("http")=3D=3D-1){return null;} =
var =
scriptAction=3DpayloadType&&payloadType.length>0?"&jsa=3D"+payloadType:"&=
jsa=3D"+PayloadType.PageView;var =
imageServer=3D"analytics.r.msn.com";if(this.ServerId){var =
newServerEndpoint=3D".analytics.live.com";if(!$assertType(this.ServerId,"=
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point.length)>255){return null;} =
imageServer=3Dthis.ServerId+newServerEndpoint;} var =
queryUrl=3Dlocation.protocol+"//"+imageServer+"/x.gif?jsv=3D"+this.Script=
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Language=3D((!document.all||navigator.userAgent.match('Opera'))?navigator=
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on.href;} =
if(document.referrer.indexOf(location.host)=3D=3D-1){this.Referrer=3Ddocu=
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this.Timezone=3Dthis.CalculateTimezone();queryUrl=3Dthis.ProcessTaxonomy(=
queryUrl);return =
queryUrl;};MicrosoftAnalytics.prototype.SetCartItem=3Dfunction(productNam=
e,unitPrice,quantity){if(!$assertType(productName,"string")){return =
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if(!$assertValue(this.ShoppingCart)){this.ShoppingCart=3Dnew =
List();this.Taxonomy.Add("ShoppingCart","crt",ListNodeType.Variable);} =
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TrackCart=3Dfunction(){if(!$assertValue(this.ShoppingCart)||this.Shopping=
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this.ImageRequest(eventPayload);};MicrosoftAnalytics.prototype.TrackPurch=
ase=3Dfunction(){if($assertValue(this.PurchaseRegistered)&&this.PurchaseR=
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this.TrackEvent("crtp",1);if(!this.PageViewRegistered){var =
eventPayload=3Dthis.SubmitPayload(PayloadType.Cart);if(!$assertValue(even=
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unction(viewId,viewHierarchy){if(!$assertValue(viewId)||!$assertValue(vie=
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if(viewId.toString().length=3D=3D0||viewHierarchy.toString().length=3D=3D=
0){return false;} if(!$assertValue(this.Views)){this.Views=3Dnew =
List();this.Taxonomy.Add("Views","vh",ListNodeType.Variable);} return =
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Event=3Dfunction(eventName,eventData,priority){if(!$assertValue(eventName=
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if(!$assertValue(this.Events)){this.Events=3Dnew =
List();this.Taxonomy.Add("Events","evt",ListNodeType.Variable);} =
this.Events.Add(this.Events.Count,new =
SimpleEvent(eventName,eventData));if(this.PageViewRegistered){this.ImageR=
equest(this.SubmitPayload(PayloadType.Event));}};function =
CartItem(productName,unitPrice,quantity){this.Name=3D$clean(productName);=
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1;} else{this.Price=3D0;this.Quantity=3D0;} =
if($assertType(quantity,"number")){this.Quantity=3Dquantity;} =
this.TotalPrice=3Dthis.Price*this.Quantity;};CartItem.prototype.toString=3D=
function(){return"prd:"+this.Name+";"+this.Price+";"+this.Quantity+"|";};=
function =
ViewHierarchy(viewId,viewStructure){this.Id=3D$clean(viewId);this.Structu=
re=3D$clean(viewStructure);};ViewHierarchy.prototype.toString=3Dfunction(=
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SimpleEvent(eventName,eventDetail){this.Name=3D$clean(eventName);this.Det=
ail=3D$clean(eventDetail);};SimpleEvent.prototype.toString=3Dfunction(){r=
eturn"e:"+this.Name+";"+this.Detail+"|";};function =
SimpleLink(linkUrl,linkType){this.Url=3D$clean(linkUrl);this.Type=3DlinkT=
ype;};SimpleLink.prototype.toString=3Dfunction(){return"l:"+this.Url+";"+=
this.Type+"|";};window["MicrosoftAnalytics"]=3DMicrosoftAnalytics;})();va=
r msAnalytics=3Dnew MicrosoftAnalytics();
------=_NextPart_000_000F_01C9F299.AFDE0150--

